Z^3-8z^2+9z+58=0

Solution for Z^3-8z^2+9z+58=0 equation:

^3-8Z^2+9Z+58=0

We add all the numbers together, and all the variables

-8Z^2+9Z=0

a = -8; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-8)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-8}=\frac{-18}{-16}
=1+1/8
$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-8}=\frac{0}{-16}
=0
$